f the pressure on a 1.00 L sample of gas is increased from 760. mmHg to 2.00 atm at constant temperature, what will the volume of the gas sample become?

The volume wuill become 0,5 liters

Explanation:

We use Boyle-Mariotte's Law, according to which at constant temperature, the pressure and volume of a gas vary inversely. We convert mmHg into atm:

760mmHg equivalent to 1atm.

P1xV1 = P2xV2

1,00atm x1,00L=2,00atmxV2

V2 = (1,00atm x1,00L) / 2,00atm=0,5 L