13. A sample of liquid water at 30.0 C is cooled to - 5.0 C,

13d. How much energy is in the system if you begin with 32.6 g of liquid water?

Q = 4389 j

Explanation:

Given dа ta:

Initial temperature = 30°C

Final temperature = - 5.0 °C

Mass of water = 32.6 g

Energy in system = ?

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m. c. ΔT

ΔT = T2 - T1

ΔT = -5°C - 30°C

ΔT = 35°C

Q = m. c. ΔT

Q = 30.0 g. 4.18 j/g.°C. 35°C

Q = 4389 j