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16 May, 11:46

How much energy is needed to heat a 35.5g sample of ice at - 17.5°C to liquid water at

77.3°C

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  1. 16 May, 12:04
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    Answer: Q = 6831.8 J

    Explanation: To solve for Q we will use the heat capacity formula:

    Q = mc∆T, where the specific heat capacity of ice is (c = 2.03 J / g°C).

    Q = 35.5 g (2.03 J / g°C) (77.3°C - (-17.5°C))

    Q = 72.065 J / °C (94.8 °C)

    Q = 6831.8 J
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