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6 June, 08:52

a balloon has a pressure of 104.5 kpa and a volume of 3.4L. If the pressure is reduced to 42.7 kpa, what will the volume change to?

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Answers (2)
  1. 6 June, 09:17
    0
    The answer to your question is 8,32 L

    Explanation:

    Data

    Pressure 1 = 104.5 kPa

    Volume 1 = 3.4 L

    Pressure 2 = 42.7 kPa

    Volume 2 = ?

    Formula

    - To solve this problem use the Boyle's law.

    P1V1 = P2V2

    - Solve for V2

    V2 = P1V1 / P2

    - Substitution

    V2 = (104.5) (3.4) / 42.7

    -Simplification

    V2 = 355.3 / 42.7

    - Result

    V2 = 8.32 L
  2. 6 June, 12:34
    0
    The new volume is 8.3 L

    Explanation:

    Step 1: Data given

    Initial pressure of balloon = 104.5 kPa = 1.0313348 atm

    Volume of the balloon is 3.4 L

    The pressure is reduced to 42.7 kPa = 0.4214162 atm

    Step 2: Calculate the new volume

    p1*V1 = p2 * V2

    ⇒p1 = the initial pressure in the balloon = 1.0313348 atm

    ⇒V1 = the initial volume = 3.4 L

    ⇒p2 = the reduced pressure = 0.4214162 atm

    ⇒V2 = the new volume

    1.0313348 atm * 3.4 L = 0.4214162 * V2

    V2 = 8.3 L

    The new volume is 8.3 L
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