sample of an ideal gas at 1.00 atm and a volume of 1.09 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 45.0 atm, what was the volume of the sample

Question

Chemistry

Nehemiah Bailey

16 May, 04:33

sample of an ideal gas at 1.00 atm and a volume of 1.09 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 45.0 atm, what was the volume of the sample

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Answers (2)

Know the Answer?

Karly Johns · Answer 1

b

Explanation:

b

Glenn Duarte · Answer 2

The answer to your question is 0.024 L

Explanation:

Data

Pressure 1 = 1 atm

Volume 1 = 1.09 L

Pressure 2 = 45 atm

Volume 2 = ?

Process

1. - To solve this problem use the Boyle's law

P1V1 = P2V2

- Solve for V2

V2 = P1V1 / P2

- Substitution

V2 = (1) (1.09) / 45

- Simplification

V2 = 1.09 / 45

- Result

V2 = 0.024 L or 24.2 mL