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23 December, 18:09

A 500 mL sample of 0.5 M NaOH at 20 C is mixed with an equal volume of 0.5 M HCl at the same temperature in a calorimeter. The temperature rises to 23.21 C. Calculate the heat of the reaction. ( - 53.72 kJ/mol)

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  1. 23 December, 19:50
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    Answer: Heat of reaction ∆H = - 13.43kJ

    Explanation:

    The number of moles of NaOH = the number of moles of HCL = N

    N = concentration * volume = CV = 0.5M * 500mL/1000ml/L

    N = 0.5 * 0.5 = 0.25mol

    Since the Molar enthalpy is given by Hm = - 53.72kJ/mol

    Heat of reaction ∆H = N*Hm

    ∆H = 0.25mol * - 53.72kJ/mol = - 13.43kJ

    Heat of reaction ∆H = - 13.43kJ
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