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18 October, 13:47

If the rate of decrease for the partial pressure of N2H4 in a closed reaction vessel is 80 torr/h, what is the rate of change for the partial pressure of NH3 in the same vessel?

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  1. 18 October, 17:10
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    Answer:Pressure of NH3 increases at the rate of 160torr/hr

    Explanation:

    According to the equation below

    N2H4 (g) + H2 (g) = => 2 NH3 (g)

    It shows that 1mol of N2H4 will gives 2mol of NH3

    Therefore, if the partial pressure rate of N2H4 is 80torr/hr, the partial pressure of NH3 increases by 2*80=160torr/hr
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