An aqueous solution that contains 285 ppm of potassium nitrate 1KNO32 is being used to feed plants in a garden. What volume of this solution is needed to prepare 2.0 L of a solution that is 75 ppm in KNO3

0.53 L

Explanation:

Given data

Initial concentration (C₁) : 285 ppm Initial volume (V₁) : ? Final concentration (C₂) : 75 ppm Final volume (V₂) : 2.0 L

We can find the required volume of the initial solution using the dilution rule.

C₁ * V₁ = C₂ * V₂

V₁ = C₂ * V₂ / C₁

V₁ = 75 ppm * 2.0 L / 285 ppm

V₁ = 0.53 L