What mass of Na2SO4 is needed to make 2.0 L of 3.0 M solution? (Na=23g; S=32g; O=16 g)

852g

Explanation:

Molarity = 3M

Volume = 2L

Molar Mass of Na2SO4 = (23x2) + 32 + (16x4) = 46 + 32 + 64 = 142g/mol

Number of mole = ?

Recall:

Molarity = mole / Volume

Mole = Molarity x Volume

Mole = 3 x 2 = 6moles

Number of mole = Mass / Molar Mass

Mass = number of mole x molar Mass

Mass of Na2SO4 = 6 x 142

Mass of Na2SO4 = 852g