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18 March, 05:52

20950 joules of heat are added to a container with 400 g of water. how much does the temperature change? Show work and formula.

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  1. 18 March, 08:20
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    The temperature change is 12.5 °C

    Explanation:

    Step 1: Data given

    20950 joules of heat are added to a container

    Mass of water = 400 grams

    Specific heat of water = 4.184 J/g°C

    Step 2: Calculate temperature change

    q = m*c*ΔT

    ⇒ with q = the heat added to the container = 20950 J

    ⇒ with m = the mass of water = 400 grams

    ⇒ with c = the specific heat of water = 4.184 J/g°C

    ⇒ with ΔT = the change of temperature

    20950 J = 400 * 4.184 * ΔT

    ΔT = 12.5 °C

    The temperature change is 12.5 °C
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