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28 June, 05:51

2HgO->2Hg+O2. I start with 46.8 g HgO. What is my theoretical yield of O2?

b. I actually collect 2.30 g of O2. What is my percent yield of O2?

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  1. 28 June, 08:23
    0
    Theoretical yield = 3.52 g

    Percent yield = 65.34%

    Explanation:

    Given dа ta:

    Mass of HgO = 46.8 g

    Theoretical yield of O₂ = ?

    Percent yield of O₂ = ?

    Actual yield of O₂ = 2.30 g

    Solution:

    Chemical equation:

    2HgO → 2Hg + O₂

    Number of moles of HgO = mass / molar mass

    Number of moles of HgO = 46.8 g / 216.6 g/mol

    Number of moles of HgO = 0.22 mol

    Now we will compare the moles of HgO with oxygen.

    HgO : O₂

    2 : 1

    0.22 : 1/2*0.22 = 0.11 mol

    Theoretical yield:

    Mass of oxygen = number of moles * molar mass

    Mass of oxygen = 0.11 mol * 32 g/mol

    Mass of oxygen = 3.52 g

    Percent yield:

    Percent yield = actual yield / theoretical yield * 100

    Percent yield = 2.30 g / 3.52 g * 100

    Percent yield = 65.34%
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