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29 June, 15:19

Hydrogen gas is collected by water displacement. If the barometric pressure is 752.0 torr and the water vapor pressure is 17.5 torr, what is the partial pressure of the hydrogen collected

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Answers (2)
  1. 29 June, 15:40
    0
    734.5 torr

    Explanation:

    Let's find the difference between the barometric pressure and the water vapour pressure

    Bp = 752 torr

    Wp = 17.5 torr

    Bp - wp

    752 - 17.5 = 734.5 torr
  2. 29 June, 17:40
    0
    Answer: The partial pressure of the hydrogen collected is 734.5 torr

    Explanation:The partial pressure of the hydrogen collected can be calculated using Dalton's law of partial pressure. Dalton's law of partial pressure states that in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of the partial pressures of the individual gases.

    Mathematically,

    P (total) = P1 + P2 + P3 + ... + Pn

    From the question,

    Parameters given:

    Barometric pressure (Total pressure) = 752.0 torr

    Water vapour pressure = 17.5 torr

    Partial pressure of hydrogen = ?

    Using,

    P (total) = P (water vapour) + P (Hydrogen)

    752.0 torr = 17.5torr + P (Hydrogen)

    P (Hydrogen) = 752.0 torr - 17.5 torr

    P (Hydrogen) = 734.5 torr

    Therefore the partial pressure of the hydrogen collected is 734.5 torr
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