For the reaction 3 C 2H 2 (g) → C 6H 6 (l) at 25°C, the standard enthalpy change is - 631 kJ and the standard entropy change is - 430 J/K. Calculate the standard free energy change at 25°C

The standard free energy change is - 502.86 KJ

Explanation:

ΔG° = H° - TΔS°

where;

ΔG° is the standard free energy

H° is the standard enthalpy change = - 631 kJ

ΔS° is the standard change in entropy = - 430 J/K

T is the temperature of the system = 25⁰C = 298 K

Applying the formula above;

ΔG° = - 631 kJ - (-0.43J/K * 298K)

= - 631 kJ + 128.14 KJ

= - 502.86 KJ

Therefore, the standard free energy change is - 502.86 KJ