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10 April, 18:45

Below is a generic equation for a reaction. If I mix 2 units of A, with 6 units of B, which of the following is true?2A + 3B? C + 3DA. There would be no reaction. B. Both reactants will fully react. C. Not enough information givenD. Substance B will be the limiting reactant. E. Substance A will be the limiting reacta

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  1. 10 April, 19:37
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    substance A will be the limiting reactant. Substance B will be in excess. Option E is correct.

    Explanation:

    Step 1: Data given

    We mix 2 units (moles) of A with 6 units (moles) of B

    Step 2: The balanced equation:

    2A + 3B → C + 3D

    Step 3: Determine the limiting reactant

    For 2 moles of A we need 3 moles of B to produce 1 mol of C and 3 moles of D

    IF A would be the limiting reactant, it means it would completely be consumed (2 units).

    B is in excess. there would react 2 * 3/2 = 3 units.

    There would remain 6 - 3 = 3 units of B

    If B would be the limiting reactant, it means it would completely be consumed (6 units).

    A would be in excess, there would react 6 * 2/3 = 4 units.

    This would be impossible.

    We can decide that substance A will be the limiting reactant. Substance B will be in excess. Option E is correct.
  2. 10 April, 19:39
    0
    E. Substance A will be the limiting reactant.

    Explanation:

    Below is a generic equation for a reaction.

    2A + 3B → C + 3DA

    According to the balanced equation, the theoretical molar ratio of A to B is 2:3, that is, 2 moles of A react with 3 moles of B.

    If I mix 2 units of A, with 6 units of B, which of the following is true?

    A. There would be no reaction. FALSE. The reaction will occur until the limiting reactant is over

    B. Both reactants will fully react. FALSE.

    C. Not enough information given. FALSE.

    D. Substance B will be the limiting reactant. FALSE. Substance B will be the reactant in excess because there are 6 moles and only 3 moles are required.

    E. Substance A will be the limiting reactant. TRUE.
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