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16 December, 12:44

A gas storage tank has a volume of 3.5 X 105 L when the temperature is 27oC, and the pressure is 101 kPa. What is the new volume of the tank if the temperature drops to - 10oC and the pressure drops to 95 kPa?

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  1. 16 December, 16:43
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    Answer: 3.26x10^5L

    Explanation:

    P1 = 101kPa

    P2 = 95kPa

    T1 = 27°C = 27 + 273 = 300k

    T2 = - 10°C = - 10 + 273 = 263k

    V1 = 3.5 x 10^5 L

    V2 = ?

    P1V1 / T1 = P2V2 / T2

    (101 x 3.5 x 10^5) / 300 = (95xV2) / 263

    300x95xV2 = 101x 3.5x10^5x263

    V2 = (101x 3.5x10^5x263) / (300x95)

    V2 = 3.26x10^5L
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