A gas storage tank has a volume of 3.5 X 105 L when the temperature is 27oC, and the pressure is 101 kPa. What is the new volume of the tank if the temperature drops to - 10oC and the pressure drops to 95 kPa?

Answer: 3.26x10^5L

Explanation:

P1 = 101kPa

P2 = 95kPa

T1 = 27°C = 27 + 273 = 300k

T2 = - 10°C = - 10 + 273 = 263k

V1 = 3.5 x 10^5 L

V2 = ?

P1V1 / T1 = P2V2 / T2

(101 x 3.5 x 10^5) / 300 = (95xV2) / 263

300x95xV2 = 101x 3.5x10^5x263

V2 = (101x 3.5x10^5x263) / (300x95)

V2 = 3.26x10^5L