Complete and balance the molecular equation for the reaction of aqueous sodium carbonate, Na 2 CO 3, and aqueous nickel (II) chloride, NiCl 2. Include physical states.

NiCl2 (aq) + Na2CO3 (aq) - --> NiCO3 (s) + 2NaCl (aq)

Explanation:

Soluble ionic compounds exist as ions in solution.

Na 2CO3, will contain Na2CO3 (aq) - -> 2Na ^ + (aq) + CO2 ^-3 (aq)

The same way, a solution of calcium chloride,

CaCl 2, will contain CaCl2 (aq) - -> Ca2^ + (aq) + 2Cl^ - (aq)

Mixing both solution, the calcium cations

Ca 2^+, will apir up with the carbonate anions, CO2^-3, and form the Insoluble calcium carbonate, CaCO ^3, which precipitates out of solution.

The complete ionic equation, which features all the ions that are present in solution, will be like this

2 Na^ + (aq) + CO2^-3 (aq) + Ca2^ + (aq) + 2Cl^ - (aq) - -> CaCO 3 ↓ (s) + 2Na^ + (aq) + 2Cl^ - (aq)

Notice that you have two sodium cations and two chloride anions on the products' side, which is why you have 2NaCl

NiCl2 (aq) + Na2CO3 (aq) - --> NiCO3 (s) + 2NaCl (aq)