Arrange the following solids in order of decreasing solubility, CaF2, K sp=4.0 * 10-11; Ag2CO3, K sp=8.1 * 10-12; Ba3 (PO4) 2, K sp=6.0 * 10-39; and Ag3 (PO4) 2, K sp=1.0 * 10-31. View Available Hint (s) Arrange the following solids in order of decreasing solubility, CaF2, K sp=4.0 * 10-11; Ag2CO3, K sp=8.1 * 10-12; Ba3 (PO4) 2, K sp=6.0 * 10-39; and Ag3 (PO4) 2, K sp=1.0 * 10-31. Ba3 (PO4) 2 > Ag3 (PO4) 2 > CaF2 > Ag2CO3 CaF2 > Ag2CO3 > Ag3 (PO4) 2 > Ba3 (PO4) 2 Ba3 (PO4) 2 > CaF2 > Ag3 (PO4) 2 > Ag2CO3 Ag2CO3 > Ba3 (PO4) 2 > Ag3 (PO4) 2 > CaF2

Question

Chemistry

Patricia Mckinney

30 June, 06:24

Arrange the following solids in order of decreasing solubility, CaF2, K sp=4.0 * 10-11; Ag2CO3, K sp=8.1 * 10-12; Ba3 (PO4) 2, K sp=6.0 * 10-39; and Ag3 (PO4) 2, K sp=1.0 * 10-31. View Available Hint (s) Arrange the following solids in order of decreasing solubility, CaF2, K sp=4.0 * 10-11; Ag2CO3, K sp=8.1 * 10-12; Ba3 (PO4) 2, K sp=6.0 * 10-39; and Ag3 (PO4) 2, K sp=1.0 * 10-31. Ba3 (PO4) 2 > Ag3 (PO4) 2 > CaF2 > Ag2CO3 CaF2 > Ag2CO3 > Ag3 (PO4) 2 > Ba3 (PO4) 2 Ba3 (PO4) 2 > CaF2 > Ag3 (PO4) 2 > Ag2CO3 Ag2CO3 > Ba3 (PO4) 2 > Ag3 (PO4) 2 > CaF2

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Answers (1)

Know the Answer?

Alyvia Juarez · Answer 1

CaF2 > Ag2CO3 > Ag3 (PO4) 2 > Ba3 (PO4) 2

Explanation:

Ksp which is solubility product konstant shows equilibrium between a solids and its respective ions in a solution. And the lower it is the less soluble the ion compound will be. And for CaF2 we have the highest konstant and for Ba3 (PO4) 2 we have it the lowest.