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27 March, 13:32

If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (205)

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  1. 27 March, 16:43
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    204.73K

    Explanation:

    the formula : PV=nRT

    n=4

    P=5.6 atm

    V=12 L

    R=0.08206 L atm mol-1 K-1

    T=?

    So, if you plug it in, you will get:-

    T=PV/nR

    T = (5.6 atm) (12 L) / (4 mol) (0.08206 L atm mol-1 K-1)

    T=204.73 K

    hope this is correct!
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