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3 November, 13:09

At a certain temperature this reaction follows first-order kinetics with a rate constant of 0.184 s^-1? Suppose a vessel contains Cl_2 O_5 at a concentration of 1.16 M. Calculate the concentration of Cl_2 O_5 in the vessel 5.70 seconds later.

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  1. 3 November, 14:15
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    0.57 M

    Explanation:

    rate = change in concentration / time

    Initial concentration of Cl2O5 = 1.16 M

    Let the concentration of Cl2O5 after 5.70 seconds be y

    rate = (1.16 - y) / 5.7

    The reaction follows a first order

    Therefore, rate = ky = 0.184y

    0.184y = (1.16 - y) / 5.7

    0.184y * 5.7 = 1.16 - y

    1.0488y + y = 1.16

    2.0488y = 1.16

    y = 1.16/2.0488 = 0.57 M

    Concentration of Cl2O5 after 5.70 seconds is 0.57 M
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