How many moles of H2 are produced from 5.8 moles of NH3

2NH3 - > N2 + 3H2

How many moles of O2 are needed to produced 1.8 moles of H2O?

C3H8 + 5O2 - > 3CO2 + 4H2O

1. 8.7moles of H2

2. 2.25moles of O2

Explanation:

1. 2NH3 - > N2 + 3H2

From the equation,

2moles of NH3 produce 3 moles of H2.

Therefore, 5.8moles of NH3 will produce Xmol of H2 i. e

Xmol of H2 = (5.8x3) / 2 = 8.7moles

2. C3H8 + 5O2 - > 3CO2 + 4H2O

From the equation,

5moles of O2 produced 4moles of H2O.

Therefore, Xmol of O2 will produce 1.8mol of H2O i. e

Xmol of O2 = (5x1.8) / 4 = 2.25moles