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30 March, 02:52

A student must use 220 mL of hot water in a lab procedure. Calculate the amount of heat required to raise the temperature of 220 mL of water from 30.0 / C to 100.0 / C. c for water is 4.184 J/g CC

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  1. 30 March, 04:32
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    64,433.6 Joules

    Explanation:

    We are given;

    Volume of water as 220 mL Initial temperature as 30°C Final temperature as 100°C Specific heat capacity of water as 4.184 J/g°C

    We are required to calculate the amount of heat required to raise the temperature.

    We know that amount of heat is calculated by;

    Q = mcΔT, where m is the mass, c is the specific heat, ΔT is the change in temperature.

    Density of water is 1 g/mL

    Thus, mass of water is 220 g

    ΔT = 100°C - 30°C

    = 70°C

    Therefore;

    Amount of heat, Q = 220g * 4.184 J/g°C * 70°C

    = 64,433.6 Joules

    Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules
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