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3 July, 07:25

During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. Theoretically, the expected amount should have been 105 grams. What was the actual yield from this reaction? CaCO3 + HCl → CaCl2 + CO2 + H2O

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  1. 3 July, 09:17
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    Actual yield = 86.5g

    Explanation:

    Percent yield = 82.38%

    Theoretical yield = 105g

    Actual yield = x

    Equation of reaction,

    CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

    Percentage yield = (actual yield / theoretical yield) * 100

    82.38% = actual yield / theoretical yield

    82.38 / 100 = x / 105

    Cross multiply and make x the subject of formula

    X = (105 * 82.38) / 100

    X = 86.499g

    X = 86.5g

    Actual yield of CaCl₂ is 86.5g
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