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25 July, 05:55

1.00 mole of oxygen at 60 degrees celcius and 5 bar is flowing through a 20cm diameter pipe (inner diameter). What is the velocity of the gas in the pipe? Can use relation u = V/A = m / p x A

where u = velocity in m/x, V = volumetric florate, A = cross sectional area, m = mass flow rate, p = density

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  1. 25 July, 08:55
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    u = 0.176 m/x

    Explanation:

    ∴ n O2 = 1 mol

    ∴ mass O2 = 1 mol * 32 g/mol = 32 g

    ∴ T = 60°C = 333 K

    ∴ P = 5 bar

    ⇒ V = RTn/P = (83.14 bar. cm³/mol. K) * (333 K) * (1 mol)) / (5 bar)

    ⇒ V = 5537.124 cm³

    ∴ d = 20cm

    ⇒ A = (1/4π) * d² = 314.16 cm²

    velocity of the gas (m/x):

    u = m / ρ*A let time (t) = x sec

    ∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³

    ∴ mass flow rate (m) = 32g / x

    ⇒ u = (32 g/x) / ((5.78 E-3 g/cm³) * (314.16cm²))

    ⇒ u = 17.625 cm/x * (m/100cm) = 0.176 m/x
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