How many moles of a gas will occupy 2.50L at STP

n = 0.112 mol

Explanation:

Given dа ta:

Volume of gas = 2.50 L

Temperature = 273 K

Pressure = 1 atm

Moles of gas = ?

Solution:

PV = nRT

n = PV/RT

n = 1 atm * 2.50 L / 0.0821 atm. L. K⁻¹. mol⁻¹. 273 K

n = 2.5 atm. L / 22.4 atm. L. mol⁻¹

n = 0.112 mol