If one wished to obtain 0.15 moles of glacial acetic acid, how many milliliters of glacial acetic acid should be obtained? Enter only the number with two significant figures.

8.6 mL

Explanation:

Glacial acetic acid (or anhydrous acetic acid) can be thought of as pure acetic acid, and has a density of 1.05 g/cm³ (or g/mL).

To answer this problem first we convert moles of acetic acid (CH₃CO₂H) to grams, using its molar mass (60 g/mol):

0.15 mol acetic acid * 60 g/mol = 9.0 g acetic acid.

Now we convert grams of acetic acid to mL, using its density:

9.0 g : 1.05 g/mL = 8.6 mL