Ask Question
17 July, 16:41

What is the number of moles of H2O produced from 221 grams of SnO2?

+3
Answers (1)
  1. 17 July, 17:40
    0
    2.932 moles

    Explanation:

    Assuming the equation for the reaction in question is;

    SnO₂ (s) + 2H₂ (g) → Sn (s) + 2H₂O (l)

    Then we can answer the question given;

    We are given;

    Mass of SnO₂ as 221 grams

    We need to calculate the number of moles of H₂O produced;

    Step 1: We determine the number of moles of SnO₂ used

    To calculate the number of moles we divide mass of of a compound by its molar mass.

    Molar mass of SnO₂ = 150.71 g/mol

    Therefore;

    Number of moles = 221 g : 150.71 g/mol

    = 1.466 moles

    Step 2: Calculate the number of moles of H₂O produced

    From the equation, 1 mole of SnO₂ reacts to produce 2 moles of H₂O

    Thus, the mole ratio of SnO₂ : H₂O is 1 : 2

    Hence; Moles of H₂O = Moles of SnO₂ * 2

    = 1.466 moles * 2

    = 2.932 moles

    Therefore, 2.932 moles of H₂O are produced.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the number of moles of H2O produced from 221 grams of SnO2? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers