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10 November, 11:03

Zinc metal reacts with hydrochloric acid according to the following balanced equation.

Zn (s) + 2HCl (aq) →ZnCl2 (aq) + H2 (g)

When 0.121 g of Zn (s) is combined with enough HCl to make 52.5 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 21.8 ∘C to 23.9 ∘C. Find the Enthalpy change (in kJ/mol) for this reaction as written. (Use 1.0g/mL for the density of the solution and 4.18 J/g * Celcius as the specific heat capacity.)

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  1. 10 November, 11:24
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    The enthalpy change is - 249.1 kJ/mole

    Explanation:

    Step 1: The balanced equation

    Zn (s) + 2HCl (aq) →ZnCl2 (aq) + H2 (g)

    Step 2: Data given

    mass of Zn = 0.121 grams

    volume of the solution = 52.5 mL = 0.0525 L

    Initial temperature = 21.8°C

    Final temperature = 23.9 °C

    Density of the solution = 1g/mL

    Specific heat capacity = 4.18 J / g°C

    Step 3: Calculating mass of solution

    mass = density * volume

    mass = 1g / mL * 52.5 mL = 52.5 grams

    Step 4: Calculate heat transfer

    Q = m*c*ΔT

    with m = mass of the solution = 52.5 grams

    with c = the specific heat capacity of the solution = 4.18 J/g °C

    with ΔT = the change in temperature = final - initial temperature = 23.9 - 21.8 °C = 2.1 °C

    Q = 52.5 grams * 4.18 J/g°C * 2.1 °C = 460.845 J

    Step 5: Calculate number of moles of Zn

    moles = mass of Zinc / Molar mass of Zinc

    moles of Zinc = 0.121 grams / 65.38 g/mol = 0.00185 moles

    Step 6: Calculate enthalpy change

    ΔHrxn = heat / moles

    ΔHrxn = 460.845 J / 0.00185 moles = 249105.4 J/mole = 249.1 kJ/mole

    Since reaction is exothermic, ΔHrxn is negative.

    ΔHrxn = - 249.1 kJ/mole
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