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3 October, 08:36

Starting from a 1 M stock of NaCl, how will you make 50 ml of 0.15 M NaCl?

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  1. 3 October, 11:54
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    We need 7.5 mL of the 1M stock of NaCl

    Explanation:

    Data given:

    Stock = 1M this means 1 mol / L

    A 0.15 M solution of 50 mL has 0.0075 moles NaCl per 50 mL

    Step 2: Calculate the volume of stock we need

    The moles of solute will be constant

    and n = M*V

    M1*V1 = M2*V2

    ⇒ with M1 = the initial molair concentration = 1M

    ⇒ with V1 = the volume we need of the stock

    ⇒ with V2 = the volume we want to make of the new solution = 50 mL = 0.05 L

    ⇒ with M2 = the concentration of the new solution = 0.15 M

    1*V1 = 0.15 * (50)

    V1 = 7.5 mL

    Since 0.0075 L of 1M solution contains 0.0075 moles

    50 mL solution will contain also 0.0075 moles but will have a molair concentration of 0.0075 moles / 0.05 L = 0.15 M

    We need 7.5 mL of the 1M stock of NaCl
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