Ask Question
30 April, 10:19

A polypeptide in its native conformation has weak interactions between its R groups. However, when that same polypeptide is denatured, these R groups similarly interact with water. Why, then, is the native structure more stable than the denatured one

+3
Answers (1)
  1. 30 April, 12:43
    0
    A protein is more stable in its native form, because apart of weak interactions between R groups, it also presents other stronger interactions, as those including covalent bonds

    Explanation:

    For example, covalent bonds between sulfur atoms when disulfide bridges are built. These links are very difficult to break and maintains the protein shape. Disulfide bonds are a few but they use to incide in the structure of native proteins
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A polypeptide in its native conformation has weak interactions between its R groups. However, when that same polypeptide is denatured, ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers