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22 December, 02:23

When a 120g sample of aluminum absorbs 9612 J of energy its temperature increases from 298K to 388K. Find the specific heat of the aluminum.

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  1. 22 December, 06:14
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    Specific heat of Aluminium is 0.89 g/J

    Explanation:

    Step 1:

    Specific heat of a substance is the energy absorbed by a substance of unit mass when its temperature increases by one degree.

    Energy Absorbed = Specific Heat * Mass of the substance * Temperature Difference

    Step 2:

    It is given that 120 g sample absorbs 9612 J energy when the temperature increases from 298K to 388K.

    Temperature Difference = 388 K - 298 K = 90 K

    Step 3:

    Specific Heat = (Energy Absorbed) : (Mass of the substance * Temperature Difference)

    Specific Heat = 9612 : (120 * 90) = 0.89 grams / Joule

    Step 4:

    Answer:

    Specific heat of Aluminium is 0.89 g/J
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