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8 August, 09:15

A 7.73 mass % aqueous solution of ethylene glycol (HOCH2CH2OH) has a density of 1.19 g/mL. Calculate the molarity of the solution. Give your answer to 2 decimal places.

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  1. 8 August, 10:58
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    Molarity for the solution is 1.48 M

    Explanation:

    Molarity involves the moles of solute that are contained in 1L of solution. It is a sort of concentration. The most usual.

    7.73 by mass involves the mass of solute that are contained in 100 g of solution, so this one of ethylene glycol contains 7.73 g of it.

    Let's determine the moles of solute

    7.73 g / molar mass of ethylene glycol = moles

    7.73 g / 62 g/mol = 0.124 mol

    If the mass of solution is 100 g, we can determine the volume with density.

    Density = Mass / Volume

    Volume = Mass / Density

    Volume = 100 g / 1.19 g/mL = 84.03 mL

    In conclusion, 0.124 moles are contained in 84.03 mL

    Molarity is mol/L, so let's convert the volume in L

    84.03 mL. 1L / 1000 mL = 0.08403 L

    0.124 mol / 0.08403 L = 1.48 M
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