What is the molarity of a 10.5 %% by mass glucose (C6H12O6C6H12O6) solution? (The density of the solution is 1.03 g/mLg/mL.) Express your answer to three significant figures.

Molarity = 54.50 M

Explanation:

Molarity is defined as the number of moles of a solute in 1 liter of solution. It has mol/l unit.

Molar mass of glucose, C6H12O6 = (6*12) + (1*12) + (16*6)

= 72 + 12 + 96 = 180g/mol

Density of glucose solution = 1.03g/ml

Density in g/l = 1.03g/ml * 1ml/10^-3l

= 1030g/l

10.5% mass of glucose = 10.5/100 * 180

= 18.9g/mol

Molarity = density (g/l) / molar mass (g/mol)

= 1030/18.9

= 54.50 M