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31 October, 15:30

Calculate the molar mass of a gas if an 8.06*10 (to the power of - 2) gram sample of it occupies. 0650 L at 547°C and 70.5 kPa

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  1. 31 October, 16:05
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    M. Mass = 120 g/mol

    Explanation:

    Data Given:

    Volume = V = 0.0650 L

    Temperature = T = 547 °C = 820.15 K

    Pressure = P = 70.5 kPa = 0.695 atm

    Gas Constant = R = 0.082057 L. atm. mol⁻¹. K⁻¹

    Formula Used:

    Assuming that the gas is ideally then according to ideal gas equation,

    P V = n R T

    Solving for n,

    n = P V / R T

    Putting Values,

    n = (0.695 atm * 0.0650 L) : (0.082057 L. atm. mol⁻¹. K⁻¹ * 820.15 K)

    n = 6.71 * 10⁻⁴ moles

    Now, Knowing that,

    Moles = Mass / M. Mass

    Or,

    M. Mass = Mass / Moles

    Putting values,

    M. Mass = 8.06 * 10⁻² g / 6.71 * 10⁻⁴ mol

    M. Mass = 120 g/mol
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