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5 December, 21:05

Balance the following half-reaction: (acidic) NO-3 (aq) → NO2 (aq) Express your answer as a half-reaction. Identify all of the phases in your answer.

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  1. 6 December, 00:56
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    2H⁺ + NO₃⁻ + 1e⁻ → NO₂ + H₂O

    Explanation:

    NO₃⁻ → NO₂

    In left side, Nitrogen acts with + 5 by oxidation number

    In right side, the oxidation number is + 4

    This is a reduction reaction, because the oxidation number has decreased. So the N has gained electrons.

    NO₃⁻ + 1e⁻ → NO₂

    In acidic medium, we have to add water, where there are less oxygens to ballance the amount. We have 2 O in left side, and 3 O in right side, so we have to add 1 H₂O on left side.

    NO₃⁻ + 1e⁻ → NO₂ + H₂O

    Now that oxygens are ballanced, we have to ballance the hydrogens by adding protons in the opposite side

    2H⁺ + NO₃⁻ + 1e⁻ → NO₂ + H₂O
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