What is the volume of 0.05 mol of neon gas at STP?

= 1.12 L

Explanation:

We are given;

Moles of neon at STP is 0.05 mol

We are required to calculate the volume;

According to molar gas volume, 1 mole of a gas occupies a volume of 22.4 liters at STP. That is, 1 mole of a gas = 2.4 L

Therefore;

1 mole of Neon gas = 22.4 L

Thus;

Volume = Moles of the gas * molar gas volume

= 0.05 mol * 22.4 L/mol

= 1.12 L

Thus, the volume of neon gas at STP is 1.12 L