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8 January, 03:00

Determine the empirical formula for a compound that contains 35.98% aluminum and 64.02% sulfur?

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  1. 8 January, 04:20
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    Al2S3

    Explanation:

    Firstly, we need to know their atomic masses. The atomic mass of sulphur is 32 while that of aluminum is 27.

    So firstly, we divide the percentage compositions with their atomic masses.

    S = 64.02/32 = 2.000625

    Al = 35.98/27 = 1.3326

    We then proceed to divide each by the smallest of the two.

    S = 2.000625/1.3326 = 1.5

    Al = 1.3326/1.3326 = 1

    Let's multiply each by 2 to yield 3 and 2 respectively.

    The empirical formula is thus Al2S3
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