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23 June, 01:21

Elvin is asked to analyze a 0.353 gram sample of metal. He measures the amount of heat

released by cooling it from 50.0 °C to 22.0 °C as 2.28 J. What is the specific heat of this metal?

What metal could this be?

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Answers (1)
  1. 23 June, 05:09
    0
    c = 0.23 j/g.°C

    The metal could be silver

    Explanation:

    Given dа ta:

    Mass of metal = 0.353 g

    Initial temperature = 50°C

    Final temperature = 22.0°C

    Heat release = - 2.28 j

    Specific heat of metal = ?

    Solution:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = T2 - T1

    ΔT = 22.0°C - 50°C

    ΔT = - 28°C

    Q = m. c. ΔT

    - 2.28 j = 0.353 g * c * - 28°C

    c = - 2.28 j / 0.353 g * - 28°C

    c = - 2.28 j / 9.884g.°C

    c = 0.23 j/g.°C

    The metal could be silver.
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