How much heat is released when 345 g of tin is cooled from 210.0 degrees * C to 0.0 C? (C = 0.220 J/gC)

Answer: 18634 joules

Explanation:

The quantity of Heat Energy (Q) released when a heated substance is cooled depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = ?

Mass of oil = 345g

C = 0.220 J/g°C

Φ = (Final temperature - Initial temperature)

= 0°C - 220°C = - 220°C

Then, Q = MCΦ

Q = 345g x 0.220 J/g°C x - 220°C

Q = 18634 joules (note that negative sign will not reflect in answer, because it only indicates that heat was released rather than gained)

Thus, 18634 joules of heat is released