If I have 31 liters of helium in a balloon at 9°C and increase the temperature of the balloon to 28°C, what will the new volume of the balloon be if the pressure remains constant? What is T2?

Answer: The new volume of the balloon is 33 liters while T2 is 301K

Explanation:

Initial volume of helium V1 = 31 liters

Initial temperature T1 = 9°C

Convert temperature in Celsius to Kelvin

(9°C + 273°C = 280K)

Final temperature T2 = 28°C

(28°C + 273°C = 301K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

31/280 = V2/301

To get the value of V2, cross multiply

V2 = (31 x 301) / 280

V2 = 9331 / 280

V2 = 33.325 liters (approximated to 33liters)

Thus, the new volume of the balloon is 33 liters while T2 is 301K