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1 September, 02:21

How many moles in 28 grams of UO2?

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Answers (2)
  1. 1 September, 03:35
    0
    There are 0.135moles of UO2 in 28 grams of UO2

    Explanation:

    The SI base unit for amount of substance is the mole. 1 mole is equal to 1 mole UO2, or 207.03grams.

    This is the molar mass of UO2, calculated from the sum of the molar masses of uranium and oxygen.

    That is, molar mass of UO2 = molar mass of U + (molar mass of O) 2

    =238.03g/mol + (16g/mol) 2

    = 238.03g/mol + 32g/mol = 270.03g/mol

    Molar mass of UO2 = 270.03g/mol

    This implies that 1 mole of UO2 has a mass of 207.03 grams

    Number of moles of UO2 = mass of UO2 / molar mass of UO2

    Mass of UO2 = 28 grams

    Number of moles of UO2 = 28 g / 207.03gmol-1

    Number of moles = 0.1352 moles of UO2

    Therefore, there are 0.135 moles of UO2 in 28 grams of UO2.
  2. 1 September, 05:40
    0
    0.22 moles.

    28 divided by 124 = 0.22
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