if a volume of air occupying 12.0Lat 20celsius is heated to a new temperature of 100 celsius, what would be the new volume

V₂ = 15.3

Explanation:

Given dа ta:

Initial volume = 12.0 L

Initial temperature = 20°C

Final temperature = 100°C

Final volume = ?

Solution:

First of all we will convert the temperature into kelvin.

20°C + 273 = 293 K

100°C + 273 = 373 K

Formula:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 12.0 L * 373 K / 293 k

V₂ = 4476 L. K / 293 k

V₂ = 15.3

V₂ = 1566 L. K / 298 K

V₂ = 5.3 L