How many grams of solid Ca (OH) 2 (74.1 g/mol) are required to make 500 ml of a 3 M solution?

111.15 g are required to prepare 500 ml of a 3 M solution

Explanation:

In a 3 M solution of Ca (OH) ₂ there are 3 moles of Ca (OH) ₂ per liter solution. In 500 ml of this solution, there will be (3 mol/2) 1.5 mol Ca (OH) ₂.

Since 1 mol of Ca (OH) ₂ has a mass of 74.1 g, 1.5 mol will have a mass of

(1.5 mol Ca (OH) ₂ * (74.1 g / 1 mol)) 111.15 g. This mass of Ca (OH) ₂ is required to prepare the 500 ml 3 M solution.