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30 November, 22:45

If a chemical reaction consumes reactants at a steady rate of 7.64 x 10^19 molecules per second, how long will it take for the reaction to consume 6.02 x 1017 molecules of reactant?

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  1. 1 December, 01:09
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    time = Molecules/Rate = > 0.0079 segs

    Explanation:

    Rate = 7.64 * 10^19 molecules/segs

    Molecules = 6.02 * 10^17 molecules

    time = #?

    time = Molecules/Rate = > 0.0079 segs
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