Find the number of grams of HCl needed to react completely with. 50 moles of magnesium. Mg (s) + 2HCl (aq) - -> MgCl2 (aq) + H2 (g)

36.46 g of HCl

Explanation:

The balance chemical equation for given single replacement reaction is as follow;

Mg + 2 HCl → MgC₂ + H₂

Step 1: Calculate Moles of HCl required:

According to equation,

1 mole of Mg reacted with = 2 moles of HCl

So,

0.5 moles of Mg will react with = X moles of HCl

Solving for X,

X = 0.5 mol * 2 mol / 1 mol

X = 1 mol of HCl

Step 2: Calculate Mass of HCl as;

Moles = Mass / M. Mass

Or,

Mass = Moles * M. Mass

Mass = 1 mol * 36.46 g/mol

Mass = 36.46 g of HCl