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4 July, 00:26

You react 105g of lithium nitride and excess water, and you get 48g of lithium hydroxide. What is the percent yield?

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  1. 4 July, 03:38
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    Percent yield = 22.26%

    Explanation:

    Given dа ta:

    Mass of lithium nitride = 105 g

    Mass of lithium hydroxide produces = 48 g

    Percent yield = ?

    Solution:

    Chemical equation:

    Li₃N + 3H₂O → 3LiOH + NH₃

    Number of moles of lithium nitride:

    Number of moles = mass / molar mass

    Number of moles = 105 g / 34.83 g/mol

    Number of moles = 3 mol

    Now we will compare the moles of lithium nitride with lithium hydroxide.

    Li₃N : LiOH

    1 : 3

    3 : 3*3 = 9 mol

    Mass of lithium hydroxide:

    Mass = number of moles * molar mass

    Mass = 9 mol * 23.95 g/mol

    Mass = 215.6 g

    Percent yield:

    Percent yield = actual yield / theoretical yield * 100

    Percent yield = 48 g / 215.6 g * 100

    Percent yield = 22.26%
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