Ask Question
3 January, 18:06

Calculate the molality of a 1.06 M sucrose, C12H22O11, with a density of 1.14 g/mL. For sucrose, mol. wt.

+1
Answers (1)
  1. 3 January, 19:44
    0
    The molality is 0.930 mol/kg

    Explanation:

    Molality = molarity : density

    Molarity of sucrose = 1.06 M = 1.06 mol/L

    Density of sucrose = 1.14 g/mL = 1.14 g/mL * 1 kg/1000 g * 1 mL / 0.001 L = 1.14 kg/L

    Molality = 1.06 mol/L : 1.14 kg/L = 0.930 mol/kg
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate the molality of a 1.06 M sucrose, C12H22O11, with a density of 1.14 g/mL. For sucrose, mol. wt. ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers