Ask Question
22 September, 20:34

Place the following in order of increasing F-A-F bond angle, where A represents the central atom in each molecule. PF3 OF2 PF4 + Group of answer choices PF3 < OF2 < PF4 + OF2 < PF3 < PF4 + PF4 + < OF2 < PF3 PF4 + < PF3 < OF2 OF2 < PF4 + < PF3 PF3 < PF4 + < OF2

+5
Answers (2)
  1. 22 September, 21:04
    0
    PF4 + < PF3 < OF2

    Explanation:

    Hello,

    In this case, the two non-shared pairs of electrons present on the OF2 occupy more space and causes the FOF bond angle to be the largest one (180°) due to its planar arrangement. Furthermore, PF3 has just 1 non-shared pair of electrons, therefore there is less space for the bonds to be trigonally arranged, it means, a smaller angle (120°). Finally, PF4 + shows a perfectly tetrahedral arrangement therefore it has the smallest bond angle (109.5°).

    Best regards.
  2. 22 September, 22:24
    0
    PF3 < OF2 < PF4+

    Explanation:

    For PF3 angle is 96.3, for OF2 it's 103 (look through internet). Due to that PF4 + ion must be completely tetrahedral angle will be 109,5
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Place the following in order of increasing F-A-F bond angle, where A represents the central atom in each molecule. PF3 OF2 PF4 + Group of ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers