Carbon disulfide gas and oxygen gas react to form sulfur dioxide gas and carbon dioxide gas. What volume of carbon dioxide would be produced by this reaction if 10L of oxygen were consumed? Also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits.

There is 3.34 L of CO2 produced

Explanation:

Step 1: Data given

Volume of oxygen = 10 L

(Assume O2 is the limiting reactant)

Step 2: The balanced equation

CS2 + 3O2 → 2SO2 + CO2

Step 3: Calculate moles of O2

22.4 L = 1 mol

10. L = 1/2.24 = 0.446 mol

Step 3: Calculate moles of CO2

For 3 moles of O2 consumed, we have 1 mol CO2 produced

For 0.446 moles of O2 we have 0.446/3 = 0.149 mol of CO2

Step 4: Calculate volume of CO2

Volume CO2 produced = 0.149 * 22.4 L = 3.34 L

There is 3.34 L of CO2 produced