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5 June, 01:59

Find the specific heat of an unknown material with an initial temperature of 20°C, when 5000 Joules are applied to a 50 gram sample and the final temperature is 70°C

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  1. 5 June, 03:09
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    2J/g°C

    Explanation:

    Q = 5000J

    Initial temperature (T1) = 20°C

    Final temperature (T2) = 70°C

    Specific heat capacity (c) = ?

    Heat energy (Q) = mc∇T

    Q = mc∇T

    Q = mc (T2 - T1)

    5000 = 50 * c * (70 - 20)

    5000 = 50c * 50

    5000 = 2500c

    c = 5000 / 2500

    c = 2J/g°C

    The specific heat capacity of the substance is 2J/g°C
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