Ask Question
7 September, 12:18

A mixture of He, Ne and Ar has a total pressure of 0.80 atm and is found to contain 0.55 mol He, 0.94 mol Ne and 0.35 mol Ar. What is the partial pressure (in atm) of each gas?

+2
Answers (1)
  1. 7 September, 14:44
    0
    Partial pressure He = 0.239 atm

    Partial pressure Ne = 0.409 atm

    Partial pressure Ar = 0.152 atm

    Explanation:

    Step 1: Data given

    Total pressure = 0.80 atm

    Number of moles He = 0.55 moles

    Number of moles Ne = 0.94 moles

    Number of moles Ar = 0.35 moles

    Step 2: Calculate total moles

    Total moles = Moles He + moles Ne + moles Ar

    Total moles = 0.55 + 0.94 + 0.35

    Total moles = 1.84 moles

    Step 3: Calculate mol fractions

    Mol fraction He = 0.55 / 1.84 = 0.299

    Mol fraction Ne = 0.94 / 1.84 = 0.511

    Mol fraction Ar = 0.35 / 1.84 = 0.190

    Step 4: Calculate partial pressure

    Partial pressure He = 0.80 atm * 0.299 = 0.239 atm

    Partial pressure Ne = 0.80 atm * 0.511 = 0.409 atm

    Partial pressure Ar = 0.80 atm * 0.190 = 0.152 atm
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A mixture of He, Ne and Ar has a total pressure of 0.80 atm and is found to contain 0.55 mol He, 0.94 mol Ne and 0.35 mol Ar. What is the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers